Trying to see if I understand Ohms law

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Discussion Overview

The discussion revolves around understanding Ohm's Law in the context of controlling current in a motor circuit. Participants explore the implications of using resistors to limit current and the associated power ratings, as well as the behavior of MOSFETs in series with resistors.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Exploratory

Main Points Raised

  • One participant proposes using a 360-ohm resistor to reduce the current from 100 amps to 30 amps in a 12-volt motor circuit, applying Ohm's Law.
  • Another participant calculates that the motor's resistance is 0.12 ohms and suggests that to achieve 30 amps, a series resistor of 0.28 ohms would be required, along with a power rating of 252 watts for the resistor.
  • There is a correction regarding the formula V * I = R, clarifying that V * I represents power, while V / I gives resistance.
  • A question is raised about the behavior of a power MOSFET rated for 50 volts and 17 amps when used in series with resistors of different values, specifically 2.2 ohms and 0.7 ohms.
  • Another participant explains the current draw for a 2.2-ohm resistor in a 12-volt circuit and the effects of adding a 0.7-ohm resistor in series, noting that a MOSFET does not generate voltage and can only conduct current when acting as a short circuit.
  • A warning is issued about the dangers of high current in vehicle electrics and the potential fire hazards associated with short circuits.

Areas of Agreement / Disagreement

Participants express differing views on the appropriate resistor values and configurations for achieving desired current levels, and there is no consensus on the best approach to take in practical applications.

Contextual Notes

Participants note the importance of understanding the implications of using resistors in motor circuits, including power ratings and the risks associated with high currents, particularly in vehicle applications.

Who May Find This Useful

This discussion may be useful for individuals interested in electrical engineering, circuit design, or those working with motors and power electronics.

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Hello
I'm trying to get my head around ohms law, and have a question.
If I have a motor that draws 12volt 100amp, and I would like to drop the amps down to 30, would I put a 360ohm resister in line.
12 * 30 = 360
V * I = R

Side note can you get a resister that is 480 watt?

Thank you

P.S I've got some nicchrome wire that I could cut to that ohm, but it would glow red hot. Would that happen to all types of reisiters that could do these.
 
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open said:
Hello
I'm trying to get my head around ohms law, and have a question.
If I have a motor that draws 12volt 100amp, and I would like to drop the amps down to 30, would I put a 360ohm resister in line.
12 * 30 = 360
V * I = R

Side note can you get a resister that is 480 watt?

Thank you

No.

The motor has a resistance of 12 / 100 or 0.12 ohms. Assume this is constant.
If you wanted to put 30 amps through this you would have a voltage across the motor of
30 amps * 0.12 ohms or 3.6 volts.

This would leave 12 - 3.6 or 8.4 volts across a series resistor which would have 30 amps flowing in it so it would be 8.4 volts / 30 amps or 0.28 ohms.
The power of the resistor would be 8.4 * 30 or 252 watts.

Note that this would not be a good thing to do to a motor. It may not even rotate with only 3.6 volts across it.

Incidentally, V * I = R is not correct. V * I = power, or V / I = R
 
No.

The motor has a resistance of 12 / 100 or 0.12 ohms. Assume this is constant.
If you wanted to put 30 amps through this you would have a voltage across the motor of
30 amps * 0.12 ohms or 3.6 volts.

This would leave 12 - 3.6 or 8.4 volts across a series resistor which would have 30 amps flowing in it so it would be 8.4 volts / 30 amps or 0.28 ohms.
The power of the resistor would be 8.4 * 30 or 252 watts.

Note that this would not be a good thing to do to a motor. It may not even rotate with only 3.6 volts across it.

Incidentally, V * I = R is not correct. V * I = power, or V / I = R

Thanks for ther quick repley.
If a powermosfet = 50 volt 17 amp, and is in serial with a 2.2ohm reisiter, will it make 17amp at 12 volt, or will a resisiter at .7ohm in serial make 17amp at 12 volt(V/I=R).
 
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open said:
Thanks for ther quick repley.
If a powermosfet = 50 volt 17 amp, and is in serial with a 2.2ohm reisiter, will it make 17amp at 12 volt, or will a resisiter at .7ohm in serial make 17amp at 12 volt(V/I=R).

If you put a 2.2 ohm resistor across a 12 volt supply, it will draw a current of 5.45 amps (12 volts / 2.2 ohms = 5.4545 Amps.)

Putting an extra 0.7 ohms in series would drop the current to 12 /(2.2 + 0.7) or 4.14 amps.

Putting just the 0.7 ohm resistor across the battery would draw a current of 17.14 amps, as you suggest.

A MOSFET does not generate voltage. This one can stand 50 volts when it is not conducting and it can conduct 17 amps when it is acting as a short circuit. The 50 volts and the 17 amps cannot happen at the same time or the MOSFET would be dissipating 850 watts. (50 volts * 17 amps = 850 watts). This is a lot of power for a small MOSFET and may blow it up.
 
OPEN,
Please do not try any of these ideas in practice until you are sure of what you are doing. It seems likely that your task involves vehicle electrics, or a vehicle-type 12V battery.

Be aware that such batteries can pass enormous currents in the case of a short-circuit.
This is a very serious fire hazard, especially when petrol (gasoline) is nearby.
 

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