Trying to solve a second order ODE

cahill8
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Homework Statement



I'm trying to solve a second order ODE for y(x) to show that the solution is y(x)=sin(x)/x. We've been told to use the substitution y(x)=h(x)/x. I've got to the stage of solving for h(x), arriving at h''(x)=-x. Using the general solution, h(x)=A sin(x) + B cos(x) and substiting this into the original equation for y(x) I get y(x)=(A sin(x) + B cos(x))/x

So all that's left to do it seems is to use the inital conditions to show A=1 and B=0 however the problem says to use the inital condition y(0)=1. This doesn't make sense to me since y is singular at x=0. Is this inital condition a mistake or am I missing something?


Homework Equations


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The Attempt at a Solution


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hi cahill8! :smile:

limx->0 sinx/x = 1 :wink:
 
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