Two Circular Motion Questions. Pendulums

AI Thread Summary
The discussion revolves around two physics problems involving circular motion and pendulums. The first problem involves calculating the angle of a conical pendulum with a length of 1.5m rotating at 4 m/s, where participants suggest using trigonometric relationships and tension equations to derive the angle. The second problem focuses on determining the necessary speed for a mass moving in a vertical circle with a string length of 2m to complete the circle, with discussions on the role of tension and gravitational forces. Participants emphasize the importance of understanding the relationship between tension, gravity, and velocity in both scenarios. Overall, the conversation highlights the complexities of applying physics concepts to solve these problems effectively.
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Homework Statement


Got my first physics assignment and I've been able to work out (I think) all of them except these two.

1. A conical pendulum has length 1.5m and rotates at 4ms^-1. What is its angle to the vertical?

2. A mass moves in a vertical circle attached to a fixed point by a string of length 2m. How fast must it be moving at the lowest point if it completes circles? What would be the speed necessary at the lowest point if the mass were attached by a light rod instead of a string?


Homework Equations


F=ma
F=mv^2/r
v=rω
ω=θ/r



The Attempt at a Solution



1. I've drawn a diagram and understand that i have gravity acting downwards and tension up the string. I think i could find θ by using tanθ=v^2/rg but I am not sure of how to work the radius out if i only have the length of the string, the velocity, and gravity.

2.
I'm only given the length and gravity on this question. I think i might have to work out the tension but I am finding it difficult without knowing a mass of the object.

I understand my attempts didn't go too far. Tension, work, and energy were omitted from my course for some reason so I've got some catching up to do with it. Thanks
 
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hi navm1! welcome to pf! :smile:

(try using the X2 button just above the Reply box :wink:)
navm1 said:
1. I've drawn a diagram and understand that i have gravity acting downwards and tension up the string. I think i could find θ by using tanθ=v2/rg but I am not sure of how to work the radius out if i only have the length of the string, the velocity, and gravity.

either eliminate T by doing F = ma for both the x and y directions,

or ignore T by choosing … which direction? :wink:
2.
I'm only given the length and gravity on this question. I think i might have to work out the tension but I am finding it difficult without knowing a mass of the object.

call the mass "m" … it'll cancel out in the end :smile:
 
Thanks
I'm still really struggling with these. Any pointers on where to start? I was told the first one will include a quadratic equation somewhere
 
navm1 said:
1. A conical pendulum has length 1.5m and rotates at 4ms^-1. What is its angle to the vertical?



Homework Equations


F=ma
F=mv^2/r
v=rω
ω=θ/r



The Attempt at a Solution



1. I've drawn a diagram and understand that i have gravity acting downwards and tension up the string. I think i could find θ by using tanθ=v^2/rg but I am not sure of how to work the radius out if i only have the length of the string, the velocity, and gravity.

Look at your diagram (or the yellow triangle on the attached picture): how is the radius r related to the length of the string and the angle θ?

ehild
 

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hi navm1! :wink:

(just got up :zzz:)
navm1 said:
I'm still really struggling with these. Any pointers on where to start?

start with F = ma for both the x and y directions (separately) …

show us what you get :smile:
 
tiny-tim said:
hi navm1! :wink:

(just got up :zzz:)


start with F = ma for both the x and y directions (separately) …

show us what you get :smile:

me too. I'm sick so its a perfect day to stay in and do physics all day.

so the force of gravity is (m)(-9.8) only in the y direction which means the y component of the tension must be (m)(9.8). the only two forces acting are gravity and tension so the x component of the tension must be providing the centripetal force on its own. so i drew a diagram for tension and ended up with (9.8)tanθ=v2/r and that's as far as i made it so far without knowing angle θ
 
navm1 said:
(9.8)tanθ=v2/r
Right so far. You know v and the length of the string. What other equation can you write relating these with θ and r?
 
navm1 said:
… (9.8)tanθ=v2/r and that's as far as i made it so far without knowing angle θ

you know L = 1.5, so what's the relation between L r and θ ? :wink:
 
i don't know if I am going down the route you guys have suggested but i ended up changing my equation from

(g)(tanθ) = v2/r

to

sinθ/cosθ = v2/(l*sinθ)(g)

then i think i could square the sinθ and start to build a quadratic equation from there?

if i multiplied both sides by sinθ would i end up with

sin2θ/cosθ = v2/lg ?

edit: or could i replace sin2θ with 1-cos2θ
 
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  • #10
so if x = cosθ
then my equation is x2+(v2/lg)*x-1=0. v2/lg

i came out with x=0.6 so cos-1 would be 53.1°
which would make the vertical angle 36.9°

am i on the right track here? thanks
 
  • #11
navm1 said:
(g)(tanθ) = v2/r

sinθ/cosθ = v2/(l*sinθ)(g)

sin2θ/cosθ = v2/lg ?

edit: or could i replace sin2θ with 1-cos2θ
navm1 said:
so if x = cosθ
then my equation is x2+(v2/lg)*x-1=0. v2/lg

yes! :smile:

how are you getting on with question 2?
navm1 said:
2. A mass moves in a vertical circle attached to a fixed point by a string of length 2m. How fast must it be moving at the lowest point if it completes circles? What would be the speed necessary at the lowest point if the mass were attached by a light rod instead of a string?
 
  • #12
tiny-tim said:
yes! :smile:

how are you getting on with question 2?

so did I get the correct angle for the vertical angle? thanks a lot for the help

Gonna start question 2 as soon as i know I've got question 1 right then I'll let you know how i get on
 
  • #13
navm1 said:
so did I get the correct angle for the vertical angle? thanks a lot for the help

looks right to me :smile:
 
  • #14
so for the second question i have the equations

v=√vi2 - 2gl(1-cosθ) and T(tension)= (mvi2 / l ) - 2mg+3mg*cosθ

are these the right equations to be using given that i only have the length of the string and nothing else?
 
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  • #15
navm1 said:
so for the second question i have the equations

v=√vi2 - 2gl(1-cosθ) and T(tension)= (mvi2 / l ) - 2mg+3mg*cosθ

(= mv2/l + mg*cosθ)

yes :smile:
 
  • #16
thanks. I am havin a little trouble working out how i'd find a velocity if i don't have an initial or final velocity. if i want to find out the speed it needs to be at 180 degrees id have theta as well as l and g but no velocity

edit: i had 0=u^2-2gl(1-cosphi) then switched final velocity to make initial velocity on the outside to try and find the velocity needed for it to reach the top where its velocity would be zero but i got a math error
 
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  • #17
navm1 said:
2. A mass moves in a vertical circle attached to a fixed point by a string of length 2m. How fast must it be moving at the lowest point if it completes circles? What would be the speed necessary at the lowest point if the mass were attached by a light rod instead of a string?

navm1 said:
thanks. I am havin a little trouble working out how i'd find a velocity if i don't have an initial or final velocity …

what is the lowest possible value of the tension if the mass moves in a complete circle? :wink:
 
  • #18
does it have to be at least 9.8N?

edit: i think if it reaches 0 near the top then the string will slack and it will start free falling affected only by mg
 
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  • #19
navm1 said:
does it have to be at least 9.8N?

edit: i think if it reaches 0 near the top then the string will slack and it will start free falling affected only by mg
Those are two different answers. Does the tension need to be at least mg or at least zero (+ a tiny bit)?
 
  • #20
(just got up :zzz:)
navm1 said:
edit: i think if it reaches 0 near the top then the string will slack and it will start free falling affected only by mg

that's much closer! :smile:

but the string will be slack only if the tension is exactly zero …

(it can't be less than zero, and) if it's greater than zero, then the string must be its full length: which means that the mass stays on the circle! :wink:

(this is very similar to the fact that something will leave a surface only if the normal force is exactly zero)
 
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