Two easy circuit-analysis problems

  • Context: Engineering 
  • Thread starter Thread starter Molecular
  • Start date Start date
Click For Summary
SUMMARY

The discussion revolves around solving two circuit-analysis problems involving Kirchhoff's laws and Thevenin's theorem. The first problem focuses on finding the voltage across an 8k resistor using Kirchhoff's current laws, where the user struggles with obtaining meaningful equations and consistently arrives at a 0 = 0 outcome. The second problem involves determining the Thevenin equivalent voltage, where the user simplifies a circuit with a 230V source and parallel resistances but questions the mechanics of combining current sources. Ultimately, the user resolves both problems but seeks alternative methods to simplify the analysis process.

PREREQUISITES
  • Understanding of Kirchhoff's Current Law (KCL)
  • Familiarity with Thevenin's Theorem
  • Proficiency in node-voltage analysis
  • Basic circuit theory concepts, including voltage and current sources
NEXT STEPS
  • Study advanced techniques for simplifying circuits, such as superposition theorem
  • Learn about mesh analysis for circuit solving
  • Explore practical applications of Thevenin's theorem in real-world circuits
  • Investigate common pitfalls in node-voltage method calculations
USEFUL FOR

Electrical engineering students, circuit designers, and anyone looking to enhance their skills in circuit analysis and problem-solving techniques.

Molecular
Messages
28
Reaction score
0
First problem:

Homework Statement



I'm supposed to find the voltage across the 8k resistor in the following circuit:
http://img79.imageshack.us/img79/4139/circuit1lk0.jpg


The Attempt at a Solution



This just seems so mindboggling easy. My first thought is to use kirckhoffs current laws on all three nodes, giving me three equations with three unknowns.

The problem is this always ends up giving me a 0 = 0 equation. I'm guessing this might be because the equation for the upper left node = 1, the down left node = 2 and the node on the right = 3, so you could say left node equations = right node equation. I don't know, at any rate I always get a 0 = 0 equation so there's no help there either.

I've also tried using the node-voltage method, but this also turns out wrong every time. Admittedly this may be calculation errors on my side, but to some extent since I can't see the paths back to whatever node I chose as the reference node I've got a feeling it won't be correct anyway.

The problem seems so easy, and I know for a fact it's supposed to be easy, but I'm somehow missing something essential here, any help would be greatly appreciated.

Problem two:
Nevermind this one, I figured it out =\

Homework Statement


I'm supposed to find the Thevénin equivalent voltage of the following circuit:
http://img156.imageshack.us/img156/9977/circuit3ab6.jpg

Again this is a somewhat easy problem.
I start by simplifying the voltage source to a power source:
230v / 20 = 11.5 A in parallel with a 20 ohm resistance and a 30 ohm resistor, which together becomes a 12 ohm resistor.

So now I've got this 11.5 A power source in parallel with a 12 ohm resistor in parallel with a 12 A power source.

First question: Considering I can now splice these two power sources together, how come I need to subtract them from each other when their current goes the same way? I know that's what I'm supposed to do, I'd just think it would be 12 + 11.5 instead of 12 - 11.5.

Second question: Aren't I correct in my observation that since the 12A current is stronger than the 11.5 one, the current after I put these together as one current source will be 0.5 but pointed downwards on the left side?

Anyway at the end I get a Tvh of -3.75, but it's not supposed to be negative. But I can't see how it's supposed to not become negative considering I'm almost positive that will be the direction of the current after adding the two sources up.

This is probably because I can't figure out the exact mechanics on adding two current sources together. All I know is I'm supposed to use kirckhoff's current law to do it, but I've really got no idea how, I just take it for granted as a rule that I can.
 
Last edited by a moderator:
Physics news on Phys.org
Ok never mind problem two, I realize why now. 11.5 ampere goes down, 12 goes up, this means that the current across the 12 ohm resistor and the other 12 ohm resistor is a total of 0.5, this has to go upwards from the left current source because the 12 ampere current is headed upwards. Phew.

Still stumped at the first question though. I'm going to try the node voltage method one more time ;o.

Edit: And don't you know it, 5 minutes after I made this thread this one was right aswell. I get -12 V. I'd still like to ask though wether this is solvable in any easier way than using the node-voltage method? As I'm fairly sure it's supposed to be.
 
Last edited:

Similar threads

Replies
15
Views
3K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 37 ·
2
Replies
37
Views
6K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K