Two-Mass Spring System: Find Position of Second Mass as a Function of Time

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SUMMARY

The discussion focuses on solving the dynamics of a two-mass spring system using normal modes. The system consists of two masses, both denoted as 'm', connected by springs with a spring constant 'k', following Hooke's law. The initial positions are x1=2 and x2=7 at t=0, while the equilibrium positions are x1=1 and x2=2. The equations of motion are expressed in the form of a second-order differential equation, \ddot{x} = Kx, where K is a constant 2x2 matrix, which must be derived to find the position of the second mass as a function of time.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Familiarity with normal modes in mechanical systems
  • Knowledge of second-order differential equations
  • Ability to manipulate matrices in the context of physics
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  • Study the derivation of equations of motion for coupled oscillators
  • Learn about normal mode analysis in mechanical systems
  • Explore methods for solving second-order differential equations
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I have a system like this:

Wall-spring-mass-spring-mass

Both springs follow Hooks law with spring-constant k.
The masses are both m.

At rest, the first mass is at x=1 and the second at x=2

At t=0 the springs are pulled so that the first mass is at x=2 and the second at x=7.

Find the position of the second mass as a function of t.
 
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You have to use normal modes. Look that up in your textbook.
 
If you are having difficulty, your first step is to write the equations of motion for x1 and x2 to be of the form

\ddot{x} = Kx

where x is a vector containing x1 and x2 and K is a constant 2x2 matrix. If you don't know what to do from there, do what Meir Achuz suggested. A typical ODE book would also have explanation on how to solve such a system of equations.
 

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