Two Masses Connected by a Pulley

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When applying Newton's Second Law, it's crucial to identify the specific mass (m) relevant to the net force (Fnet) being analyzed. For two masses connected by a pulley, Fnet should correspond to the mass of interest, such as m1 or m2, rather than the total mass. The technique of cutting the rope can help determine tension by simplifying the system. Understanding which object's net force you are calculating ensures accurate application of the law. Clarity on these points will enhance confidence in solving problems involving Newton's Second Law.
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I have a general question about how to apply Newton's Second Law. When we write Fnet=ma, I am sometimes unsure of myself what the 'm' is in the problem.

For instance, when two masses (m1 and m2) are connected by a pulley is 'm' equal to m1+m2, or just the mass of interest?

How can I be absolutely sure of myself when I am solving problems using Newton's Second Law?

Does this have something to do with the technique of cutting (i.e. if two people are pulling opposite ends of a rope, then by cutting the rope, one can find the rope's tension.)?
 
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brentd49 said:
How can I be absolutely sure of myself when I am solving problems using Newton's Second Law?

Newton's second law says that the net force acting on an object is equal to that object's mass times its acceleration.

Just be sure that you know which net force you are calculating, i.e. which object you are applying Newton's second law to. If Fnet refers to the net force on mass 1, then it is given by m1 * a1, by Newton's second law. If it refers to the net force on mass 2, then it is given by m2 * a2.


If you include both masses (and assume the rope has negligible mass), then you are calculating the net force on the system, and have to be sure to multiply this mass by the acceleration of the system, which is...?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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