Two objects being pushed by one force what is the force on the second? object

  • Thread starter Thread starter nyjets2428
  • Start date Start date
  • Tags Tags
    Force
AI Thread Summary
In the scenario, a 4.0 kg block is pushed by a 100.0 N force on a frictionless surface, which in turn exerts a force on a 6.0 kg block in contact with it. To determine the force on the 6.0 kg block, free body diagrams for both blocks should be drawn. By applying Newton's second law (Ʃforces = ma) to each block, two equations can be established to solve for the unknown contact force between the blocks. The interaction between the blocks is crucial for understanding the force distribution. This approach will clarify how the applied force affects both blocks.
nyjets2428
Messages
1
Reaction score
0
A block of mass 4.0 kg lies on a frictionless horizontal table in contact with a 6.0 kg block. At the opposite side of the 4.0 kg block, a constant horizontal force of 100.0 N is applied as shown in the diagram. What is the magnitude of the horizontal force on the 6.0 kg block?

I do not know where to start with this. I am confused on how this would work. I understand that the 4 kg blocks force will be pushing the 6 kg block. but how do i figure this out
 
Physics news on Phys.org
Draw free body diagrams for each block separately.
Call the contact force between the blocks R.

For each block, write Ʃforces = ma.
This should give you two equations and two unknowns.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top