Two-point source interference pattern

AI Thread Summary
The discussion revolves around calculating the angles of nodal lines in a two-point source interference pattern created by in-phase sources. The sources are spaced 2.0 m apart, operating at a frequency of 1.0 Hz, with a wavelength of 0.60 m. Participants suggest using the formula sin(theta) = (n - 0.5)(λ/d) and substituting various integer values for n. While it may seem tedious, only a limited number of n values will yield relevant results, and using a spreadsheet can streamline the calculations. The focus remains on efficiently determining the angles for the nodal lines in the interference pattern.
12physics
Messages
2
Reaction score
0

Homework Statement



A two-point source interference pattern is generated by sources operating in phase at 1.0 Hz. The sources are 2.0 m apart and the wavelength of the waves is 0.60 m. At what angles, measured from the centre line of the pattern, are the nodal lines produced located?



They want to sub in for various values of n? or am i missing something it seems to simple? i am using sintheta=(n-0.5)(\lambda/d)
 
Physics news on Phys.org
Welcome to PF!
Yes, sub in n = 1, 2, 3, ... It looks like an infinite amount of work, but you will find that only a few values of n need be worked out. It is a little repetitive - a spreadsheet formula would be quickest!
 
thanks
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top