Two slides have different angles, find the numeric angle

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To solve for the acceleration a on the second slide, it is essential to analyze the forces acting on the child. Since the first slide has no acceleration, the forces are balanced, indicating that the gravitational component is equal to the frictional force. For the second slide, the net force can be expressed in terms of the angles theta1 and theta2, leading to the equation a = g(sin(theta2) - sin(theta1)). When theta1 is 45° and theta2 is 61°, substituting these values into the equation provides the numerical value of a. Understanding the relationship between the angles and the gravitational force is crucial for solving the problem effectively.
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In a playground, two slides have different angles of incline theta1 and theta2 (theta2 > theta1). A child slides down the first at constant speed; on the second, his acceleration down the slide is a. Assume the coefficient of kinetic friction is the same for both slides. (a) Find a in terms of
theta1, theta2, and g. (b) Find the numerical value of a for theta1 = 45° and theta2 = 61°.


I hate to post and run, but my trig skills are HORRIBLY lacking in this arena. Can any of you offer tips for solving (a)? thanks
 
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since the first angle, theta1, resulted in no acceleration, what do we know about the forces involved?
 
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