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Two slit interference

  1. Dec 3, 2007 #1
    1. The problem statement, all variables and given/known data

    Using a conventional two-slit apparatus with light of wavelength 540 nm, 33 bright fringes per centimeter are observed on a screen 3.8 m away. What is the slit separation?

    2. Relevant equations
    m/x = (2*theta)/wavelength = number of fringes per meter
    interence maxima
    dsin(theta) =m*(wavelength)

    3. The attempt at a solution
    i tried solving for theta then using that value to find slit separation d but i am totally confused.
  2. jcsd
  3. Dec 3, 2007 #2
    i got the answer.
    fringe spacing = ((wavelength)*L)/d
    L = distance to screen
    d = slit separation

    the fringe spacing would be the inverse of 33fringes per cm or ((3300)/m)^-1 then just solve for d
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