<uk,v> -> <u,k> for all v. prove uk goes to u.

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The discussion focuses on proving that if the inner product converges to for all vectors v in Rn, then the sequence {uk} converges to the vector u. The proof utilizes pointwise convergence by demonstrating that each component of the sequence {uk} converges to the corresponding component of u. Additionally, an example is sought where converges to while {uk} does not converge to u, prompting a discussion on the selection of a vector w to illustrate this scenario.

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<uk,v> --> <u,k> for all v. prove uk goes to u.

Homework Statement


a)supposed for all v in Rn <uk,v>--> <u,v> prove {uk}-->u
b)give an example of a sequence {uk} st. <uk,v> for some vector v. but uk does not converge to u.

Homework Equations


def of convergence.


The Attempt at a Solution


a)since this works for all v. we can let v1={1,0,0,...} then u1 --> u. now let v2={0,1,0,0,...} then u2 --> u.
so we keep doing this and each term of uk converges to a term in u.
so by point wise convergence we have convergence.

b) I don't know how to do this part. for a) i think i got it right but i can't come up with an example.
 
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your proof looks good. For the example, note that if uk converges to u then uk + w converges to u + w. Can you think of a way to choose w so that <uk + w, v> converges to <u, v>?
 


You have the right idea for part 1 but you aren't writing it very well. Remember that each uk is a vector. So it doesn't make sense to say u1 --> u. u1 is a fixed vector. It might help you to adopt a notation where the components of, for example u1 are u1(1), u1(2),...u1(n), and try making the argument you are thinking of.

Once you get the notation down you may see how to do the second part too.
 

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