Ultimate Guide to Solving Combinatorics Problems | Learn with :zzz: Tricks

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The discussion focuses on solving combinatorics problems, emphasizing the importance of simplifying complex problems and identifying patterns. Participants seek clarification on specific questions regarding arrangements and subsets, particularly concerning how to ensure no two identical elements are adjacent. The conversation includes attempts to calculate the number of arrangements and subsets, with references to specific formulas and methods. There is a sense of confusion among participants, with requests for further explanations and assistance on particular problems. Overall, the thread highlights the challenges faced in combinatorial reasoning and the collaborative effort to find solutions.
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2. Reduce the problem to a simpler one and find a pattern. For example, in a 2x2 square only 4 triangles have this property.
3. Could you give the exact wording of the question or rephrase it? I am unsure if you mean one quarter of all subsets of integers 1,2,3...m with three elements or not.
 
1> How many arrangements are there such that no two A's are beside each other?
2> shouldn't be a problem ... straightforward (only thing to remember ... 3 points cannot be collinear)
3> how many 3-subsets can you form? (call this A)
How many 3-subsets can contain integer 5? (call this B)
1/4 * A = B ... solve for m
4> no three segments cross at any point ...
therefore atmost two segments can cross each other ...
and every crossing of two segments produces 1 intersection point ...
so ??

-- AI
 
Could you give the exact wording of the question or rephrase it? I am unsure if you mean one quarter of all subsets of integers 1,2,3...m with three elements or not.

a subset with 3 elements

TR.. I am so lost

could u explain it a lil more?

and number one i know its ez but I can't seem to get it
 
1> How many arrangements are there such that no two A's are beside each other?

a .. First arrange the B's and y's? in how many ways can u do this?
b .. amongst 6 B's and 7 y's there are 14 places where i can place A (why do i do this ? u see this way no two A will be beside each other)
c .. in how many ways can i arrange the A's in these 14 places

Can u proceed from here ... ??

shouldn't be a problem ... straightforward (only thing to remember ... 3 points cannot be collinear)

Look at what i gave in the brackets ... can u see how to pick the points then?

how many 3-subsets can you form? (call this A)
How many 3-subsets can contain integer 5? (call this B)
1/4 * A = B ... solve for m

Can u find A and B? (atleast A is pretty simple)

4> no three segments cross at any point ...
therefore atmost two segments can cross each other ...
and every crossing of two segments produces 1 intersection point ...
so ??

How many segments are given?
In how many ways can i choose 2 segments out of the given number of segments?

-- AI
 
TR.. ur help is greatly appreciated

A .. First arrange the B's and y's? in how many ways can u do this?
you can arrange this in 13! ways because that's how many total letters there are?

i LOST you from here :(

Look at what i gave in the brackets ... can u see how to pick the points then?


This i don't get at all


Can u find A and B? (atleast A is pretty simple)
got this thanks

and the last one i don't get at all too

man... i raped the test on this unit, but the teahers chellenge sets are HARD
 
Anyone?
 
can the mods delte this thread pleez
 
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