Uncertainty about answer for Conservation of Momentum Problem

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Homework Help Overview

The problem involves the conservation of momentum and energy in a system consisting of a man, a gun, and a bullet. The scenario is set on frictionless ice, and the discussion focuses on the effects of firing the bullet on the man's speed and the energy transformations involved.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the calculation of the man's speed after firing the gun using conservation of momentum. There are questions regarding the classification of the collision as elastic or inelastic, with some expressing uncertainty about the underlying concepts.

Discussion Status

Some participants have provided feedback on calculations, and there is acknowledgment of errors in energy calculations. The classification of the collision type has been discussed, with one participant suggesting it is inelastic due to the change in kinetic energy.

Contextual Notes

Participants are grappling with the definitions of elastic and inelastic collisions, indicating a need for clarification on these concepts. There is also a focus on ensuring the accuracy of energy calculations before and after the bullet is fired.

zozajiek
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Homework Statement



A man holding a gun ((mass of man)+(mass of gun)+(mass of bullet)=60kg)) skates on frictionless ice at an initial speed of +2 m/s and fires a 100 gram bullet with a speed of +500 m/s from the gun.

a) What is the speed of the man after firing the gun? (be sure to include +/- direction)

b) What is the initial total energy of the man-gun-bullet system (before the bullet is fired)? What is the final total energy of the man-gun-bullet system (just after the bullet is fired)?

c)is this an example of an elastic, inelastic, or perfectly inelastic collision, and why? I don't understand this concept very well.


Homework Equations



Pi=Pf

M1V1i + M2V2i = M1V1f + M2V2f

Total KE (before)= .5MV^2

Total KE (after)= .5M1V1^2 + .5M2V2^2


The Attempt at a Solution



I think this is correct, but I'm not completely sure.
I'm not sure if its elastic or inelastic, I have trouble understanding that stuff.

60*2=59.9*v+.1*500
v=1.17 m/s

energy before is
.5*60*4 J
120 J

after
.5*.1*500^2+.5*59.9*1.17^2 J
12541 J
 
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Recheck value of energy after.
 
sorry it took me so long to get back on, what did I do wrong?
 
You didn't. I did while calculating. Sorry.

This is an example of an inelastic collision, because the KE before and after are not the same. The extra KE is coming from the chemical energy of the gunpowder, which was converted to mechanical energy.
 
=) thank you very much
 

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