Engineering Understanding a RL - RC circuit

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To determine the frequency at which the impedance of an RL-RC circuit is purely resistive, one must analyze the resonant frequency where the inductive and capacitive reactances cancel each other out. The circuit's total impedance can be expressed as a complex equation, combining real and imaginary components based on the values of the resistors, inductor, and capacitor. When the circuit reaches this condition, the magnitudes of the capacitive and inductive impedances will be equal, resulting in zero imaginary impedance. This frequency can be calculated using the formulas for inductive and capacitive reactance. Understanding these relationships is crucial for navigating the complexities of the circuit.
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I´m trying to understand a circuit that is build like this:

----###R1###---###C###----
###---------###----------###
-----###L###---###R2###---

How am I supposed to find what frequency (not f=0) the impedance is pure resistive?

What I´ve read has it something to do with the resonant frequency. Is that correct?

And the last question is how big are the impedance when that happens?

I´m totaly lost in this jungle.

Thanks in advance!

//Null_Null
 
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Welcome to the PF, nul_nul_

It's a little hard to interpret the circuit drawn like that. Would it be possible for you to draw it in Paint or Visio or something, and save it as a JPEG and upload it as an attachment?

Also, do you know a bit yet about how to express the impedances as complex quantities, and add them using the regular series and parallel combination rules?
 
Thank you!

Yes, I see that now. So I´ve made up one with my Paint skills :smile:

I know a bit about that. So we say we have the values of L = 5 mH, C = 22 uF, R1 = 300 ohm and R2 = 500 ohm. Then the R1 is 300 L 0 degrees, R2=500 L 0 degrees (L=Phasor) and the X(L)=2(pi)fL and phasor 90 degrees, X(C)=1/(2(pi)fC) and phasor -90 degrees.

Is this a good start and how about the frequency?

Appreciate your help!

//Null_null
 

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null_null_ said:
Thank you!

Yes, I see that now. So I´ve made up one with my Paint skills :smile:

I know a bit about that. So we say we have the values of L = 5 mH, C = 22 uF, R1 = 300 ohm and R2 = 500 ohm. Then the R1 is 300 L 0 degrees, R2=500 L 0 degrees (L=Phasor) and the X(L)=2(pi)fL and phasor 90 degrees, X(C)=1/(2(pi)fC) and phasor -90 degrees.

Is this a good start and how about the frequency?

Appreciate your help!

//Null_null

Yes, that's an excellent start. Now use parallel and series combination rules to come up with one equation for the impedance across the whole circuit. It will be a complex equation, with real and imaginary parts that depend on frequency.

EDIT -- And remember that the impedance will look "purely resistive" when there is no imaginary impedance, right? What can you say about the relative magnitudes of the capacitive (-j) and inductive (+j) impedances when this condition is met?
 

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