Understanding Circular Motion: The Importance of F=(mv^2)/r in Mass Spectrometry

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F=(mv^2)/r is crucial for understanding circular motion in mass spectrometry, as it relates the force acting on ions to their mass and velocity. When ions exit the electric field, they are influenced solely by the magnetic field, causing them to follow a circular path. To determine the radius (r) of this path, one can analyze the geometry of the semicircular trajectory the ions take before impacting the detection plate. The radius can often be derived from the known parameters of the system, such as the magnetic field strength and the velocity of the ions. Understanding this relationship is essential for accurate measurements in mass spectrometry.
v_pino
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I managed to do part a) of the question but got stuck on b). Why use F=(mv^2)/r for circular motion? And even if I use this equation, how do I find r, the radius?

Thank you
PV
 

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When the ions leaves the electric field, they are only affected by the magnetic field and will therefor move in a circle. Altough they will only finnish half of the circle before they hit the plate. So, if you have a semicircle, where can you find the radius of the circle?
 
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