Understanding Complex Numbers: Limits & Functions

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
chaoseverlasting
Messages
1,051
Reaction score
3
[SOLVED] Complex Numbers

A very happy new year to all at PF.

Homework Statement


Kreyszig, P.665 section 12.3,

A function f(z) is said to have the limit l as z approaches a point [tex]z_0[/tex] if f is defined in the neighborhood of [tex]z_0[/tex] (except perhaps at [tex]z_0[/tex] itself) and if the values of f are "close" to l for all z "close" to [tex]z_0[/tex]; that is, in precise terms, for every positive real [tex]\epsilon[/tex] we can find a positive real [tex]\delta[/tex] such that for all z not equal to [tex]z_0[/tex] in the disk [tex]|z-z_0|<\delta[/tex], we have

[tex]|f(z)-l|<\epsilon[/tex]...(2)

that is, for every z not equal to [tex]z_0[/tex] in that [tex]\delta[/tex] disk, the value of f lies in the disk (2).

I think this means that if you were to plot z and f(z), for all values of z near the point [tex]z_0[/tex] (within the [tex]\delta[/tex] disk), but not necessarily at [tex]z_0[/tex] itself (as the function may not exist at [tex]z_0[/tex]), the value of f(z) would be very close to l (but not necessarily l, as [tex]f(z_0)[/tex] may not exist) and that this value of f(z) would be inside the [tex]\epsilon[/tex] disk.

Is that right?
 
Physics news on Phys.org
Congrats, you just understood what a limit is.
 
Thank you.