- #1

cohomology

- 2

- 0

[itex]\lim_\rightarrow (\mathbb{Z} \rightarrow \mathbb{Z} \rightarrow \mathbb{Z} \rightarrow \cdots)[/itex]

where each map is multiplication by 2.

I concluded that the solution is [itex]\mathbb{Z}\sqcup\coprod(\mathbb{Z}-2\mathbb{Z})[/itex]. Is this correct?