Understanding Elastic Collisions: Solving a Head-On Collision Problem

AI Thread Summary
In an elastic collision problem, a 6 gram ball moving north at 3 m/s collides with an identical ball moving south at 2 m/s, resulting in the first ball moving south at 1 m/s. The key issue raised is the apparent contradiction in energy conservation, as the expected velocity of the second ball is questioned. The solution guide suggests the second ball moves off at 2.0 m/s, which leads to confusion regarding energy conservation principles. Participants express skepticism about the problem's wording and its implications for physical laws. Clarification is sought on whether the problem is misworded or if it presents an unrealistic scenario in physics.
cybernerd
Messages
26
Reaction score
0

Homework Statement



A 6 gram ball moving north at a rate of 3 m/s collides head on with an identical ball moving south at 2.0 m/s. The collision is elastic and the first ball moves south at 1 m/s. What is the velocity of the second ball?

Homework Equations



Law of conservation of momentum.
p=mv

The Attempt at a Solution



The question makes no sense to me. According to my solution guide, the other ball moves off at 2.0 m/s. But of the collision is elastic, then no energy should be wasted. So...2.0m/s worth of energy from the first ball is sucked into an abyss? Can anyone shed light on this?
 
Physics news on Phys.org
Yeah I don't know about this one. Energy's definitely not conserved using the given data. Chalk it up to a miswording?
 
I hope so, or we're getting into magic rather than physics...thanks for confirming this...
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
2
Views
2K
Replies
4
Views
2K
Replies
6
Views
2K
Replies
4
Views
3K
Replies
4
Views
5K
Replies
5
Views
2K
Replies
16
Views
2K
Back
Top