Understanding Fajans Rule: Ion Depletion & Valency Change

AI Thread Summary
Fajans' rule relates to the changes in ionic character and valency during radioactive decay processes. After alpha emission, the remaining product has a valency of 2, while beta emission results in a valency increase of 1 due to changes in proton count. The discussion emphasizes that altering the nuclear composition affects the electronic structure, leading to adjustments in valency. Understanding these changes is crucial for grasping the implications of Fajans' rule. Clarifying the initial valency before alpha emission can help in comprehending the overall process.
loza17
Messages
2
Reaction score
0
fajans rule??

hey can anyone help me with fajans rule?

after the emission of alpha rays from a radioactive substance the product remaining has a valency of 2. after the emission of beta rays it has a valency increase of 1. so the ionic depletion changes the valency.

thus meaning reducing the ions changes the valency

is this right?
 
Last edited:
Physics news on Phys.org
What does this have to do with Fajan's rules?

In any case, the important thing to keep in mind is that it is harder to change the nuclear composition (number of protons and neutrons) than the electronic composition. Once the number of protons is changed, the resulting ion will attract or throw away the necessary number of electrons to stay neutral. So, if the atom gains/loses n protons through radioactive decay, it will then pick up/throw out n electrons as well.

With this in mind, make sure you can follow what is happening with the atom above. What would have been the valency before alpha emission? Do the subsequent changes in valency make sense?
 
thats what my tutor taught me and i was confused about it. thanks for the help =]
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top