Undergrad Understanding forces on a balanced ladder

  • Thread starter Thread starter issacnewton
  • Start date Start date
  • Tags Tags
    Forces
Click For Summary
The discussion centers on understanding why the frictional force F at point A passes through point O in the context of a balanced ladder against a wall. It explains that in equilibrium, the net torque about any point, including point O, must be zero. By analyzing the torques exerted by forces W and R, which act along their respective imaginary levers, it becomes clear that for the sum of torques to remain zero, force F must also act along the line connecting points O and A. This conclusion is drawn from the requirement that the torque exerted by F about point O must also be zero. The explanation clarifies the relationship between the forces and their points of application in maintaining equilibrium.
issacnewton
Messages
1,035
Reaction score
37
Hello

I have a question about the explanation given for the attached image about the balanced ladder on a wall. At the end the sentence says that, "Consequently the frictional force F at A passes through O". I am not able to understand why this is so. Can anybody please shed light on this statement ?

Thanks
 

Attachments

  • Capture.PNG
    Capture.PNG
    32.8 KB · Views: 536
Physics news on Phys.org
In an equilibrium situation, the net torque (about any point) of the applied forces is zero. For example, we can pick a point P on the page off to left of the diagram and unconnected to anything by a physical lever. If we draw imaginary levers from P to the points A,G,and B and compute the net torques on those imaginary levers cause by the forces at A,G, and B, then the net torque will be zero.

If we look at the point O, the net torques about O should be zero. The torques about O exerted by the forces W and R are zero because those R acts directly along the imaginary lever drawn from O to point B and W acts directly along the imaginary lever drawn from O to G. For the sum of torques to be zero, the torque exerted about O by force F must also be zero. Hence F must act directly along an imaginary lever drawn from O to A. This implies the direction of F is along the line AO.
 
Thanks Stephen... makes sense
 
Topic about reference frames, center of rotation, postion of origin etc Comoving ref. frame is frame that is attached to moving object, does that mean, in that frame translation and rotation of object is zero, because origin and axes(x,y,z) are fixed to object? Is it same if you place origin of frame at object center of mass or at object tail? What type of comoving frame exist? What is lab frame? If we talk about center of rotation do we always need to specified from what frame we observe?

Similar threads

  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
5
Views
5K
  • · Replies 40 ·
2
Replies
40
Views
6K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K