Understanding Harmonics in Music: The Physics Behind Playing Flute Notes

AI Thread Summary
Harmonics on the flute allow players to produce two pitches using the same fingerings by varying airspeed. This phenomenon occurs because of the flute's acoustics, where specific air pressure and speed create different resonances. In higher octaves, the same fingering can yield only one audible note due to the flute's physical properties and the way sound waves interact. Understanding these principles can enhance a flautist's ability to control sound production. The discussion highlights the complexity of flute acoustics and the importance of airspeed in achieving harmonic notes.
dt19
Messages
46
Reaction score
0
i'm a flautist. sometimes i have to play notes called harmonics, where the finger position is the same (i.e. same holes closed off) but you have to vary the air speed so that you can hear the original note and also another note above it in pitch. can anyone explain to me why it is that i can hear both notes? because for some notes in the higher octaves, the fingering is the same as for notes in the lower octave, but i can only hear one note. what's the physics behind it?

apologies if that's not very easy to understand - I'm not a very articulate person.
 
Physics news on Phys.org
dt19 said:
i'm a flautist. sometimes i have to play notes called harmonics, where the finger position is the same (i.e. same holes closed off) but you have to vary the air speed so that you can hear the original note and also another note above it in pitch. can anyone explain to me why it is that i can hear both notes? because for some notes in the higher octaves, the fingering is the same as for notes in the lower octave, but i can only hear one note. what's the physics behind it?
The physics of a flute is a bit complicated. Have a look http://www.phys.unsw.edu.au/~jw/fluteacoustics.html#overview"for detailed explanation.

AM
 
Last edited by a moderator:
aha! enlightenment.

cheers.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top