- #1
Silviu
- 624
- 11
Can someone explain to me (or point me towards a source) how is the Lorenz Gauge derived? I am reading the Griffiths book and from what I understand we can do the transformation ##A' = A + \nabla \lambda## and at the same time ##V' = V - \frac{\partial \lambda}{\partial t}## and B and E remain unchanged. This is pretty obvious for the Coulomb gauge (in finding ##\lambda## to satisfy the condition). But for the Lorenz gauge if you try to find ##\lambda## from the first equation, it will be a function of V and when you plug it in ##V' = V - \frac{\partial \lambda}{\partial t}##, V' will be different from V so the V you used in ##\nabla A = -\mu_0 \epsilon_0 \frac{\partial V}{\partial t}## is not anymore the same? So how do you prove it?