Understanding Magnetic Dipoles: Forces and Equations Explained

  • Thread starter Thread starter pervect
  • Start date Start date
  • Tags Tags
    Dipoles Magnetic
AI Thread Summary
Magnetic dipoles, such as spinning electrons and current loops, generate forces and fields described by equations similar to those for electric dipoles. A current loop with area A and current i has a magnetic dipole moment defined as μ = iA, with the moment often expressed as a vector perpendicular to the area. The torque on a dipole in an external field is given by the cross product of the dipole moment and the magnetic field, while the energy in the field is represented by the negative dot product of the two. The net force on a dipole in a constant magnetic field is zero, but a varying magnetic field can produce a net force based on the gradient of the field. Understanding these principles is crucial for applications involving magnetic dipoles in various fields of physics.
pervect
Staff Emeritus
Science Advisor
Homework Helper
Insights Author
Messages
10,404
Reaction score
1,587
here seems to be some interest in magnetic dipoles, such as spinning electrons, and current loops. So I thought I would start a thread and present some of the relevant equations that describe the forces and fields generated by magnetic dipoles. These equations are very similar to those for electric dipoles, BTW.

A current loop with an area A and carrying a current i has a
magnetic dipole moment of \mu = i A. The dipole moment is sometimes expressed as a vector \vec{\mu} in which case the vector is perpendicular to the area A.

Some useful properties of the diople moment are given below

Torque generated by an external field \vec{\mu} \times \vec{B}

Energy in an external field -\vec{\mu} \cdot \vec{B}

Field from dipole at distant points along axis |B| = \frac {\mu_0}{2 \pi} \frac {\mu}{r^3}

Field from dipole at distant points along bisector |B| = \frac {\mu_0}{4 \pi} \frac {\mu}{r^3}

Field from dipole, vector form \vec{B} = \frac {\mu_0 \mu}{4 \pi r^3} (2 cos(\theta) \vec{r} + sin(\theta) \vec{\theta})

Net force on dipole from a constant magnetic field zero

Net force on a dipole from a varying magnetic field \nabla (\vec{\mu} \cdot \vec{B})

Note that the force between two dipoles will drop off with the 4th power of the distance - as the field generated by a dipole is proportional to 1/r^3, the gradient of the field is proportional to 1/r^4, and the force will be the dipole moment multiplied by the field gradient.
 
Last edited:
Physics news on Phys.org
pervect said:
Net force on dipole from a constant magnetic field zero

Net force on a dipole from a varying magnetic field \nabla (\vec{\mu} \cdot \vec{B})

"Constant" or "varying" usually means w.r.t. time. I think here you mean w.r.t. space, so common usage is "uniform" or "non-uniform".
 
krab said:
"Constant" or "varying" usually means w.r.t. time. I think here you mean w.r.t. space, so common usage is "uniform" or "non-uniform".

Yes, that's what I mean. To develop a net force, one needs the field to be different at the two ends of the dipole, which means that the field must be varying in space.
 
This is from Griffiths' Electrodynamics, 3rd edition, page 352. I am trying to calculate the divergence of the Maxwell stress tensor. The tensor is given as ##T_{ij} =\epsilon_0 (E_iE_j-\frac 1 2 \delta_{ij} E^2)+\frac 1 {\mu_0}(B_iB_j-\frac 1 2 \delta_{ij} B^2)##. To make things easier, I just want to focus on the part with the electrical field, i.e. I want to find the divergence of ##E_{ij}=E_iE_j-\frac 1 2 \delta_{ij}E^2##. In matrix form, this tensor should look like this...
Thread 'Applying the Gauss (1835) formula for force between 2 parallel DC currents'
Please can anyone either:- (1) point me to a derivation of the perpendicular force (Fy) between two very long parallel wires carrying steady currents utilising the formula of Gauss for the force F along the line r between 2 charges? Or alternatively (2) point out where I have gone wrong in my method? I am having problems with calculating the direction and magnitude of the force as expected from modern (Biot-Savart-Maxwell-Lorentz) formula. Here is my method and results so far:- This...

Similar threads

Back
Top