Understanding Normed Linear Spaces: Convergence in C[0,1]

  • Context: MHB 
  • Thread starter Thread starter bugatti79
  • Start date Start date
  • Tags Tags
    Convergence Linear
Click For Summary
SUMMARY

This discussion focuses on the convergence of sequences in normed linear spaces, specifically within the context of the space C[0,1]. It establishes that a sequence fn converges to a function f in C[0,1] with respect to the supremum norm, which implies convergence under the integral norm as well. The key takeaway is that convergence in normed spaces parallels convergence in ordinary metric spaces, utilizing the concept of epsilon-delta definitions to formalize the notion of convergence.

PREREQUISITES
  • Understanding of normed linear spaces
  • Familiarity with the supremum norm and integral norm
  • Knowledge of convergence concepts in metric spaces
  • Basic mathematical analysis skills
NEXT STEPS
  • Study the properties of normed linear spaces in detail
  • Explore the definitions and applications of the supremum norm and integral norm
  • Learn about the epsilon-delta definition of convergence in metric spaces
  • Investigate examples of convergence in C[0,1] with various norms
USEFUL FOR

Mathematicians, students of analysis, and anyone interested in functional analysis or the properties of normed linear spaces.

bugatti79
Messages
786
Reaction score
4
Folks,

I am looking at this task.

1) What does it mean to say a sequence converges in a normed linear space?

2) Show that if a sequence fn converges to f in C[0,1] with sup norm then it also converges with the integral norm?

Any idea on how I tackle these?

thanks
 
Physics news on Phys.org
bugatti79 said:
1) What does it mean to say a sequence converges in a normed linear space?

2) Show that if a sequence fn converges to f in C[0,1] with sup norm then it also converges with the integral norm?
Do you know about sequence convergence in an ordinary metric space, say the real and/or complex numbers?
If so, then you have the same idea using the norm. After all, is that not how absolute value works?
 
Plato said:
Do you know about sequence convergence in an ordinary metric space, say the real and/or complex numbers?
If so, then you have the same idea using the norm. After all, is that not how absolute value works?

Is it something along the line of

given $\epsilon > 0 $ there exist $ n_0 \in N$ s.t $|(fn-f) (x)|| < \epsilon $ for $n > n_0$ and $ x \in [a,b] $

ie $\forall \epsilon > 0$ there exist $n_0 \in N$ s.t $sup |(f_n-f)(x)|=sup|f_n(x)-f(x)|$ and $x \in [a,b]$ for both...
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 18 ·
Replies
18
Views
7K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
Replies
1
Views
1K