MHB Understanding Normed Linear Spaces: Convergence in C[0,1]

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In normed linear spaces, a sequence converges if, for every ε > 0, there exists an N such that the norm of the difference between the sequence and the limit is less than ε for all terms beyond N. Specifically, in the context of C[0,1] with the sup norm, convergence means that the supremum of the absolute differences between the sequence and the function approaches zero. The discussion also highlights that if a sequence converges in the sup norm, it will also converge in the integral norm due to the relationship between these norms. The convergence criteria can be expressed mathematically, emphasizing the supremum condition. Understanding these concepts is crucial for tackling the posed tasks effectively.
bugatti79
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Folks,

I am looking at this task.

1) What does it mean to say a sequence converges in a normed linear space?

2) Show that if a sequence fn converges to f in C[0,1] with sup norm then it also converges with the integral norm?

Any idea on how I tackle these?

thanks
 
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bugatti79 said:
1) What does it mean to say a sequence converges in a normed linear space?

2) Show that if a sequence fn converges to f in C[0,1] with sup norm then it also converges with the integral norm?
Do you know about sequence convergence in an ordinary metric space, say the real and/or complex numbers?
If so, then you have the same idea using the norm. After all, is that not how absolute value works?
 
Plato said:
Do you know about sequence convergence in an ordinary metric space, say the real and/or complex numbers?
If so, then you have the same idea using the norm. After all, is that not how absolute value works?

Is it something along the line of

given $\epsilon > 0 $ there exist $ n_0 \in N$ s.t $|(fn-f) (x)|| < \epsilon $ for $n > n_0$ and $ x \in [a,b] $

ie $\forall \epsilon > 0$ there exist $n_0 \in N$ s.t $sup |(f_n-f)(x)|=sup|f_n(x)-f(x)|$ and $x \in [a,b]$ for both...
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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