Understanding Op-Amp Integrator: Why the Ramping Effect?

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The discussion centers on the mechanics of an op-amp integrator and the resulting ramping effect in its output. The integrator processes the input voltage over time, with the output voltage reflecting the voltage across the capacitor. The ramping effect arises from the integration of voltage, influenced by the resistor-capacitor (RC) time constant, which determines how quickly the output responds to changes in input. The participant expresses confusion about the role of time in this process, realizing that the time dependency is crucial for understanding the ramping behavior. Clarification on the time factor and its impact on the integrator's output is sought for better comprehension.
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I'm having trouble understanding how this actually works. I understand that it integrates the input voltage and that the output voltage is the same as the voltage passing over the capacitor in the circuit. What i don't understand is why this causes the ramping effect?
I'm thinking it may have to do with one voltage being integrated by the integrator with relation to the capacitor and the resistor which creates a different value for the voltage which then gets integrated...etc. which then causes different values which plotted on a graph would give the ramp effect.
Is this how it works? thanks for the help.
 
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I just realized i neglected the time that this takes to happen. As its due to a certain time interval I am not sure whether what i originally assumed is correct. Now I am confused as to where time fits in with all this.
 
Sorry i realized i didnt take the fact that it is time dependant into my assumption. In this case I am even more confused heh.
 
Does this help? Or do you still have specific questions about the simple inverting integrator:

http://courses.ece.uiuc.edu/ece486/labs/lab1/386_op_amp.pdf
 
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