Understanding pH: Solving Confusing Problems with Strong Acids and Bases

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The discussion centers on calculating the pH of concentrated solutions of hydrochloric acid (HCl) and sodium hydroxide (NaOH). For 12.1 M HCl, the calculation yields a pH of approximately -1.08, which is valid as strong acids can produce negative pH values when their concentration exceeds typical limits. This phenomenon occurs due to complete dissociation in aqueous solutions, leading to unusual results that deviate from Ostwald's dilution principle. Participants clarify that while negative pH values are uncommon, they are not unexpected in highly concentrated solutions. The confusion regarding the extent of negativity in pH values is acknowledged, with a reminder that values can indeed be significantly lower than zero.
nautica
I know this is simple, but I am a bit confused

1) find the pH of 12.1 M HCl - the negative log gives me -1.8. What am I doing wrong

2) 50% NaOH (roughly 15 M) - I am not sure how to do this one either

thanks
nautica
 
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Well, HCL is a strong acid, so it dissociates completely in ions. Of course aqueous solution.

HCl + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}

H_{3}O^+ \approx H^+

I get pH -log(12.1) = -1.08, are you sure is 12.1 M?

Well, i barely remember my freshman chemistry, wait for more help.
 
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What's wrong? You are allowed to have pH values that are negative and that are also above 14.
 
If the concentration is beyond the limits of Ostwald's dilution principle, then some weird results like this is likely to occur, as gravenenewworld said in a different way. Nautica, your findings of negative pH and pOH values are normal, as these are very concentrated and are not obeying the principle.
 
Thanks, I was aware that pH could be negative, but I did not realize they would get that negative. I was thinking around zero and negative 0.5 or so.

thanks
Nautica
 
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