Understanding Power Dissipation in Parallel Resistors

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In a parallel resistor configuration, each resistor shares the current, resulting in a total resistance calculated by the formula 1/Rtotal = 1/R1 + 1/R2 + ... For ten 100-ohm resistors in parallel, the effective resistance is 10 ohms. Each 5-watt resistor contributes to the overall power dissipation, allowing for a combined total of 50 watts. This means the collective resistors can handle the power load effectively. Understanding these principles clarifies how power dissipation works in parallel circuits.
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Ok, I'm not an EE student, nor do I really understand all of the P=IE^2 stuff concerning power and resistance, etc.

My question is regarding the power dissipation abilities of resistors in paralell. Let's say I have (10) 100ohm/5w resistors in paralell. Would this effectively be a 10ohm load with 50w of power dissipation? Do the collective resistors share the power handling duties? Or am I way off?

Any insight (in layman's terms) would be much appreciated.
 
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Yes.


When in parallel each resistor handles a part of the current. 1/Rtotal = 1/R1 + 1/R2 + ...

So for 10 100R resistors you get a net resistance of 10R. Each resistor contributes to the total wattage. If each resistor is 5W then you have a total of 50W.
 
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