Understanding Relative Humidity and Dew Point in Air Masses

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An air mass at 90 degrees F with 20 grams of vapor/m^3 has a relative humidity that can be calculated by dividing the vapor content by the saturated vapor density at that temperature. If the temperature increases to 100 degrees F, the relative humidity will change due to the altered saturation point. The dew point corresponds to the temperature where the air mass reaches saturation at 20 g/m^3, which can be determined using vapor pressure data. When the temperature drops to 50 degrees F, the air mass will lose water vapor equal to the difference between its current vapor content and the saturated vapor density at that lower temperature. Understanding these concepts is crucial for predicting weather patterns and humidity levels.
Esoteric
An air mass is at 90 degrees F. It contains 20 grams of vapor/m^3. What is the relative humidity of this air mass?

What would the relative humidity of this air mass be if its temperature were increased to 100 degrees F?

What is the dew point of this air mass?

The temperature is now expected to drop to 50 degrees F. How much water vapor (g/m^3) do you expect the air mass to lose?
 
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guess not.
 
Esoteric said:
An air mass is at 90 degrees F. It contains 20 grams of vapor/m^3. What is the relative humidity of this air mass?

What would the relative humidity of this air mass be if its temperature were increased to 100 degrees F?
What is the saturated vapour density of water at 90 degrees F in g/m^3? Divide 20 by that number and you will have the relative humidity. To work the density out from the vapour pressure, if you can't find it on a table, you will have to use the ideal gas equation.

What is the dew point of this air mass?
The dew point is the temperature at which 20 g/m^3 is the saturated vapour density of water. Work out what this is in terms of pressure and just go down the graph of vapour pressure vs. temperature to find this temperature.

The temperature is now expected to drop to 50 degrees F. How much water vapor (g/m^3) do you expect the air mass to lose?
Find the saturated vapour density of water at 50F and subtract that from 20 g/m^3. That is the amount of mass/m^3 of water that will precipitate out.

AM
 
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thanks a lot Gamma and Mason.
 
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