Understanding SHM Equations: Solving Two Equations and Identifying Mistakes

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The discussion focuses on solving equations related to simple harmonic motion (SHM) and identifying mistakes in the interpretation of results. The equations provided indicate that the amplitude is A and angular frequency is 2ω for one equation, while another shows an amplitude of 2A and angular frequency of ω. The maximum speed is calculated as the product of amplitude and angular frequency, which is consistent across both cases. However, confusion arises regarding the correct answer options, with the participant concluding that Option 3 is correct despite the provided answer being Option 2. Ultimately, the participant clarifies that the origin is not at the maximum position for the SHM in question.
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Homework Statement


2Shm.jpg


Homework Equations

The Attempt at a Solution



y = 2Acos2ωt = A(1+cos2ωt)

y-A = Acos2ωt . This is SHM with origin at y = A i.e at the maximum position .

Is that correct ?

Amplitude is A and angular frequency is 2ω .

y= A(sinωt+√3cosωt) = 2Asin(ωt+π/3)

Amplitude is 2A and angular frequency is ω .

Maximum speed is product of amplitude and angular frequency .

Product is same in both the cases .

This makes Option 3) correct .

But given answer is option 2) .

What is the mistake ?
 

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Jahnavi said:
This is SHM with origin at x = A i.e at the maximum position .
Origin is x = A, yes, but it is definitely not the maximum position of this SHM.

Jahnavi said:
This makes Option 3) correct .

But given answer is option 2) .

What is the mistake ?
Option C is correct.
 
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