Understanding SHM: Velocity of a Mass on a Spring at Max Displacement

  • Thread starter Thread starter Dx
  • Start date Start date
  • Tags Tags
    Vibrations Waves
AI Thread Summary
In simple harmonic motion (SHM), when a mass on a spring reaches its maximum displacement from equilibrium, its instantaneous velocity is zero. This is because, at this point, the mass must stop momentarily before reversing direction. The discussion clarifies that just before reaching maximum displacement, the velocity is positive, and just after, it becomes negative, indicating a change in direction. The consensus is that the speed at the extremes of position is indeed zero. Understanding this concept is crucial for grasping the dynamics of SHM.
Dx
I am curious to know that if a mass on a spring undergoes SHM. when the mass is at its MAX displacement from equilibrium, its instantaneous velocity is what?
is it zero!

can someone explain?
Dx :wink:
 
Physics news on Phys.org
Well, just before the mass hits the max displacement, the velocity is +deltaV, and just after it is -deltaV. You have to go through zero to get from + to -.
 
Okay!

Dx scratches his head.
I said at MAX displacement that deltav is + or - Max but my teacher says I am wrong. It must be less than max but not zero as youve kinda explained, i think
Dx :wink:

Right?
 
You had it right the first time: The speed at the extrema of position is zero.

If you are moving this way ----->
and then this way <-----

then at some point you had to stop[/color] and turn around.
 
Kool

Hello,

Thanks!
Dx :wink:
 
Last edited by a moderator:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top