Understanding Snell's Law: Common Mistakes and Troubleshooting Tips

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Homework Statement



See figure attached for problem statement.

Homework Equations





The Attempt at a Solution



I'm getting a disagreement in my equations so I must be doing something wrong.

We have two unknowns,

[tex]n_{1},\theta_{2}[/tex]

My first equation,

[tex]n_{1}sin\theta_{1}=n_{2}sin\theta_{2}[/tex]

my second equation (This is where I think I am misunderstanding something)

Since it is experiencing total internal reflection,

[tex]\theta_{2} = arcsin\frac{n_{1}}{n_{2}}[/tex]

Or in other words,

[tex]sin\theta_{2} = \frac{n_{1}}{n_{2}}[/tex]

If I plug this into my first equation I get an inconsistency because,

[tex]sin\theta_{1} \neq 1[/tex]

What am I doing wrong?
 

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jegues said:

Homework Statement



See figure attached for problem statement.

Homework Equations





The Attempt at a Solution



I'm getting a disagreement in my equations so I must be doing something wrong.

We have two unknowns,

[tex]n_{1},\theta_{2}[/tex]

My first equation,

[tex]n_{1}sin\theta_{1}=n_{2}sin\theta_{2}[/tex]

my second equation (This is where I think I am misunderstanding something)

Since it is experiencing total internal reflection,

[tex]\theta_{2} = arcsin\frac{n_{1}}{n_{2}}[/tex]  This should be:  90° ‒ θ2= arcsin(n1/n2),
which is: sin(90° ‒ θ2) = cos(θ2) = (n1/n2)


Or in other words,

[tex]sin\theta_{2} = \frac{n_{1}}{n_{2}}[/tex]

If I plug this into my first equation I get an inconsistency because,

[tex]sin\theta_{1} \neq 1[/tex]

What am I doing wrong?

See comment in red above.
 
SammyS said:
See comment in red above.

Thank you.