Yes, given a fixed deceleration rate, stopping distance is proportional to the square of the starting speed. It makes sense that this should be so. It takes twice as long to slow down and during the slowdown interval, it is moving twice as fast.
Yes, for a fixed angular deceleration rate, the angle traversed during the slowdown is proportional to the square of the starting rotation rate. The same reasoning applies.
Of course, the deceleration rate is not always going to be equal. No matter how fast you swing your fist, it will usually stay attached to the end of your arm. Your muscles, tendons and ligaments will apply whatever force they are able to preserve that situation. Swinging twice as fast will not work to strike a fellow standing on the opposite side of the boxing ring.