Understanding the Breakdown Voltage of a Zener Diode

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Discussion Overview

The discussion revolves around the breakdown voltage of a Zener diode, focusing on the behavior of voltage and current in the breakdown region. It explores the characteristics of the Zener effect, the voltage-current relationship, and the implications of dynamic resistance.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant questions why the voltage does not vary beyond the breakdown voltage in a Zener diode.
  • Another participant asserts that the voltage does vary and explains that the dynamic resistance (rz) is finite and changes with current (Iz).
  • A different participant confirms the existence of a voltage-current curve, noting its sharp knee and attributing this to the Zener effect based on tunneling.
  • Another contribution provides a detailed explanation of the Zener effect, describing how a high reverse-bias voltage leads to tunneling and the generation of free charge carriers, resulting in significant conductance above the breakdown voltage.

Areas of Agreement / Disagreement

Participants express differing views on the behavior of voltage beyond the breakdown voltage, with some asserting that it does vary while others emphasize the characteristics of the Zener effect. The discussion remains unresolved regarding the precise nature of voltage behavior in this context.

Contextual Notes

The discussion includes assumptions about the characteristics of the Zener diode and the interpretation of the voltage-current curve, which may depend on specific conditions or definitions not fully explored in the posts.

Amrutha.phy
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Why doesn't the voltage vary beyond breakdown voltage in zener diode?
 
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In fact, it does vary. The finite slope of the Iz-Vz characteristic is expressed in form of a dynamic (differential) resistance rz which assumes rather small values (some ohms).
More than that, this value (the slope) is not constant but varies with the current Iz.
 
Last edited:
It does.

There is a voltage-current curve, it just has a sharp knee.

The reason the knee is so sharp is because the Zener effect is based on tunneling.
 
To answer your basic question, from https://en.wikipedia.org/wiki/Zener_effect

"Under a high reverse-bias voltage, the p-n junction's depletion region expands, leading to a high strength electric field across the junction. A sufficiently strong electric field enables tunneling of electrons from the valence to the conduction band of a semiconductor leading to a large number of free charge carriers. This sudden generation of carriers rapidly increases the reverse current and gives rise to the high slope conductance of the Zener diode."

So, a reverse biased diode has a non-destructive breakdown voltage, above which it has significant conductance compared to below it.
 
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