Understanding the Concept of Double Conjugate in Complex Functions

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SUMMARY

The discussion focuses on the concept of double conjugate in complex functions, specifically examining the relationship between a function \( f(z) \) and its conjugate \( f^*(z^*) \). It is established that if \( f(z) = u(x,y) + iv(x,y) \), then \( f(z^*) = u(x,-y) + iv(x,-y) \) and consequently \( f^*(z^*) = u(x,-y) - iv(x,-y) \). This confirms that the conjugate operations effectively reverse the imaginary component while maintaining the real component.

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  • Understanding of complex functions and notation
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  • Knowledge of real and imaginary components in complex numbers
  • Basic grasp of coordinate representation in the complex plane
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Mathematicians, students of complex analysis, and anyone interested in the properties and applications of complex functions will benefit from this discussion.

ognik
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Hi, I am not sure what $ {f}^{*}({z}^{*}) $ means?
I think the '*'s cancel, ie $ {f}(z) = u(x,y) + iv(x,y), \: \therefore f({z}^{*}) = u(x,y) - iv(x,y), , \: \therefore {f}^{*}({z}^{*}) = u(x,y) + iv(x,y) $ ?
Thanks
 
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Hi ognik,

If $z$ is represented by the point $(x,y) \in \Bbb R^2$, then $z^* = (x,-y)$. So given $f(z) = u(x,y) + iv(x,y)$, we have $f(z^*) = u(x,-y) + iv(x,-y)$ and hence $f^*(z^*) = u(x,-y)-iv(x,-y)$.
 
Crystal! Thanks Euge.
 

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