Understanding the Gibbs Phenomenon in Fourier Series

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Homework Help Overview

The discussion revolves around a problem related to Fourier series and the Gibbs Phenomenon, specifically focusing on a limit involving a summation and an integral. The original poster expresses uncertainty about the problem's setup and the appearance of a variable 't' that was not previously mentioned.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster seeks clarification on the origin of the variable 't' and suggests it may involve a substitution or a standard integral. Some participants restate the problem without providing further insights, while one participant indicates they resolved their confusion regarding a variable misidentification.

Discussion Status

The discussion includes attempts to clarify the problem's elements, with some participants providing hints and others expressing their own confusion. There is a recognition of a resolution by one participant, but no explicit consensus on the broader problem remains evident.

Contextual Notes

The original poster mentions this question is the last in an assignment, indicating potential constraints related to time or understanding of prior material. There is also a note about the use of LaTeX for clarity in mathematical expressions.

joriarty
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Show that [PLAIN]http://img829.imageshack.us/img829/3411/screenshot20101011at115.png

I really don't know where to start with this. It is the very last question of an assignment on Fourier series and the Gibbs Phenomenon, if that is relevant I can give more details but I don't think it is. It's just algebra from here.

I have no idea where the 't' has come from (not mentioned at any earlier stage in the assignment), but I think this might be some sort of substitution? Perhaps it is some sort of standard integral I'm not familiar with?

Could I please have a hint if you can see how this could be done? Thanks :)
 
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\lim _{N \rightarrow \infty} \frac 4 \pi \sum ^{N-1} _{n=0} \frac {\sin(\frac {(2n+1)\pi} {2n})} {2n+1} = \frac 2 \pi \int _0 ^\pi \frac {\sin (t)} {t} dt

:wink:
 
Borek said:
\lim _{N \rightarrow \infty} \frac 4 \pi \sum ^{N-1} _{n=0} \frac {\sin(\frac {(2n+1)\pi} {2n})} {2n+1} = \frac 2 \pi \int _0 ^\pi \frac {\sin (t)} {t} dt

:wink:

I'm not sure what you're trying to say there, beyond restating the initial problem. I just managed to figure it out anyway, I had an 'n' in there that should have been an 'N'. Problem solved, assignment done :D
 
I have seen you struggling with the LaTeX and finally deciding to post an image - as you see, forum LaTeX is perfectly capable of displaying the formula.
 

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