Understanding the Q Factor in Parallel Resonant Circuits

AI Thread Summary
The discussion clarifies the Q factor in parallel resonant circuits, noting that while the Q factor of the inductor and the entire parallel LC tank circuit are closely related, they are not identical. The formula Q = wL/R applies to the inductor, where R is the inductor's series resistance, but the overall Q factor for the tank circuit can differ based on component quality. High-quality capacitors minimize losses, making the inductor's resistance more significant in determining the circuit's Q factor. The conversion of the inductor's series resistance to parallel resistance using Rp = R/Q^2 simplifies analysis in circuit design. Understanding these relationships is crucial for accurate circuit performance evaluation.
appoos
Messages
2
Reaction score
0
hi there..in some places, i saw the usage "the Q factor of parallel LC tank ckt" while in some others, the Q factor of the inductor used in tank ckt is given..are they same??
As far as i know,Q=wL/R is the thing for inductor ,where R is inductor's series resistance..is the formula same for the entire parallel tank ckt??

Also, i would like to know why, during analysis, do we convert series R of inductor to parallel resistance by formula, Rp =R/Q^2 ??
 
Last edited:
Engineering news on Phys.org
appoos said:
hi there..in some places, i saw the usage "the Q factor of parallel LC tank ckt" while in some others, the Q factor of the inductor used in tank ckt is given..are they same??
Close to being the same. Low-loss capacitors are easy to find, so most of the losses are in the coil.
As far as i know,Q=wL/R is the thing for inductor ,where R is inductor's series resistance..is the formula same for the entire parallel tank ckt??
Practically, provided you use high quality capacitors. But that's not DC resistance.
Also, i would like to know why, during analysis, do we convert series R of inductor to parallel resistance by formula, Rp =R/Q^2 ??
It probably makes analysis easier.

Welcome to PF.
 
thank you..
 
Very basic question. Consider a 3-terminal device with terminals say A,B,C. Kirchhoff Current Law (KCL) and Kirchhoff Voltage Law (KVL) establish two relationships between the 3 currents entering the terminals and the 3 terminal's voltage pairs respectively. So we have 2 equations in 6 unknowns. To proceed further we need two more (independent) equations in order to solve the circuit the 3-terminal device is connected to (basically one treats such a device as an unbalanced two-port...
suppose you have two capacitors with a 0.1 Farad value and 12 VDC rating. label these as A and B. label the terminals of each as 1 and 2. you also have a voltmeter with a 40 volt linear range for DC. you also have a 9 volt DC power supply fed by mains. you charge each capacitor to 9 volts with terminal 1 being - (negative) and terminal 2 being + (positive). you connect the voltmeter to terminal A2 and to terminal B1. does it read any voltage? can - of one capacitor discharge + of the...
Back
Top