Understanding the Q Factor in Parallel Resonant Circuits

AI Thread Summary
The discussion clarifies the Q factor in parallel resonant circuits, noting that while the Q factor of the inductor and the entire parallel LC tank circuit are closely related, they are not identical. The formula Q = wL/R applies to the inductor, where R is the inductor's series resistance, but the overall Q factor for the tank circuit can differ based on component quality. High-quality capacitors minimize losses, making the inductor's resistance more significant in determining the circuit's Q factor. The conversion of the inductor's series resistance to parallel resistance using Rp = R/Q^2 simplifies analysis in circuit design. Understanding these relationships is crucial for accurate circuit performance evaluation.
appoos
Messages
2
Reaction score
0
hi there..in some places, i saw the usage "the Q factor of parallel LC tank ckt" while in some others, the Q factor of the inductor used in tank ckt is given..are they same??
As far as i know,Q=wL/R is the thing for inductor ,where R is inductor's series resistance..is the formula same for the entire parallel tank ckt??

Also, i would like to know why, during analysis, do we convert series R of inductor to parallel resistance by formula, Rp =R/Q^2 ??
 
Last edited:
Engineering news on Phys.org
appoos said:
hi there..in some places, i saw the usage "the Q factor of parallel LC tank ckt" while in some others, the Q factor of the inductor used in tank ckt is given..are they same??
Close to being the same. Low-loss capacitors are easy to find, so most of the losses are in the coil.
As far as i know,Q=wL/R is the thing for inductor ,where R is inductor's series resistance..is the formula same for the entire parallel tank ckt??
Practically, provided you use high quality capacitors. But that's not DC resistance.
Also, i would like to know why, during analysis, do we convert series R of inductor to parallel resistance by formula, Rp =R/Q^2 ??
It probably makes analysis easier.

Welcome to PF.
 
thank you..
 
While I was rolling out a shielded cable, a though came to my mind - what happens to the current flow in the cable if there came a short between the wire and the shield in both ends of the cable? For simplicity, lets assume a 1-wire copper wire wrapped in an aluminum shield. The wire and the shield has the same cross section area. There are insulating material between them, and in both ends there is a short between them. My first thought, the total resistance of the cable would be reduced...
Hi all I have some confusion about piezoelectrical sensors combination. If i have three acoustic piezoelectrical sensors (with same receive sensitivity in dB ref V/1uPa) placed at specific distance, these sensors receive acoustic signal from a sound source placed at far field distance (Plane Wave) and from broadside. I receive output of these sensors through individual preamplifiers, add them through hardware like summer circuit adder or in software after digitization and in this way got an...
I am not an electrical engineering student, but a lowly apprentice electrician. I learn both on the job and also take classes for my apprenticeship. I recently wired my first transformer and I understand that the neutral and ground are bonded together in the transformer or in the service. What I don't understand is, if the neutral is a current carrying conductor, which is then bonded to the ground conductor, why does current only flow back to its source and not on the ground path...
Back
Top