Understanding the W Boson: How are New W Bosons Created?

  • Thread starter Thread starter Mightymcc
  • Start date Start date
  • Tags Tags
    Boson W boson
Mightymcc
Messages
1
Reaction score
0
So if W bosons decay so quickly from what are new W boson made? Is it made of an electron and anti-electron neutrino (which is what they decay into) but then again this wouldn't make sense since it is an "elementary" particle. Please clear my confusion.
 
Physics news on Phys.org
W bosons are elementary particles, they do not "contain" anything. They can be created in high-energetic collisions, if a lepton is transformed into a neutrino (or vice versa), or an up-type quark goes into a down-type quark (or vice versa).
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top