Understanding Torque: Explaining the Concept to Peter

  • Thread starter Thread starter Peter P.
  • Start date Start date
  • Tags Tags
    Torque
AI Thread Summary
Torque is a measure of rotational force and is crucial for understanding how engines perform under different loads. It is defined by the equation Power = Torque x RPM, indicating that low torque may limit an engine's effectiveness at varying loads. Diesel engines typically produce higher torque at lower RPMs, making them ideal for heavy machinery, while gasoline engines reach peak power at higher RPMs. This difference explains why a diesel engine feels more powerful at the same horsepower rating compared to a gasoline engine. Ultimately, torque is essential for vehicle acceleration and managing load, while horsepower reflects the rate of work done.
Peter P.
Messages
23
Reaction score
0
Out of curiosity, I decided that I would build a Tesla Turbine and possibly use it for some interesting contraption. Except, when I was reading about it, I always heard that it can achieve high RPM, but has low torque.

I was just wondering if someone would be able to explain the concept of torque, what it does/what it's used for, and what not. I've tried reading up about it, but I'm still having trouble grasping exactly what it's for.

Thanks, Peter.
 
Engineering news on Phys.org
Power is torque x rpm and a scaling factor that dependes on your units.

So low torque means the engine may be less suitable for a varying load that drags the rpm down at times.

This is why diesel engines that have higher torque at low rpms are more common for heavy machines and tractors etc.

For example a Diesel car engine typically gives peak power at sa 3000 rpm, while a gasoline engine typically gives peak power at 6000 rpm. This is also why in practice, a diesel car at 130 hp is usually perceived as way more powerful than a gasoline car on 130 hp, since you need to whip the gasoline car to scream to get the spec out of it.

/Fredrik
 
Torque has to do with coping with the load. Power is always Torque multiplied by rpm. If you want to do work quickly, you would like to have more rpm in the equation, if you want to cope with more load and speed isn't important to you, you got to have more torque. If you again want to have a heavier load tackled at a higher rate, you got to step up both rpm value and torque.
 
Torque is analgous to force but deals with rotation. Think of Newtons Second Law, F=m*a. If a net force F is applied to an object of mass m, it will accelerate at acceleration rate of a. Similarily, if a net torque is applied to a rotating system that has a mass moment of inertia of I, it will accelerate at a rate according to T=I*alpha where alpha is the rotational acceleration.

Engine torque is what causes vehicles to accelerate. If the engine provides torque T to the driven wheel's axle, the force on the pavement that pushes the vehicle ahead is F=T/R where R is the distance from the center of the driving axle to the pavement.

Horsepower is the rate at which work is being done.
 
How did you find PF?: Via Google search Hi, I have a vessel I 3D printed to investigate single bubble rise. The vessel has a 4 mm gap separated by acrylic panels. This is essentially my viewing chamber where I can record the bubble motion. The vessel is open to atmosphere. The bubble generation mechanism is composed of a syringe pump and glass capillary tube (Internal Diameter of 0.45 mm). I connect a 1/4” air line hose from the syringe to the capillary The bubble is formed at the tip...
Thread 'Physics of Stretch: What pressure does a band apply on a cylinder?'
Scenario 1 (figure 1) A continuous loop of elastic material is stretched around two metal bars. The top bar is attached to a load cell that reads force. The lower bar can be moved downwards to stretch the elastic material. The lower bar is moved downwards until the two bars are 1190mm apart, stretching the elastic material. The bars are 5mm thick, so the total internal loop length is 1200mm (1190mm + 5mm + 5mm). At this level of stretch, the load cell reads 45N tensile force. Key numbers...
I'd like to create a thread with links to 3-D Printer resources, including printers and software package suggestions. My motivations are selfish, as I have a 3-D printed project that I'm working on, and I'd like to buy a simple printer and use low cost software to make the first prototype. There are some previous threads about 3-D printing like this: https://www.physicsforums.com/threads/are-3d-printers-easy-to-use-yet.917489/ but none that address the overall topic (unless I've missed...
Back
Top