The discussion focuses on solving a homework problem involving water pressure using the equations P2=P1+pgh. The initial attempt incorrectly suggests plugging in values directly without properly applying the formula. It clarifies that 1.3x10^5 pascals is the pressure in chamber 2, not chamber 1. To find the pressure in chamber 1, users are advised to rearrange the formula for pressure to calculate force using the known area. The conversation emphasizes the importance of correctly applying the given equations to arrive at the right solution.
#1
yesshh
3
0
Homework Statement
Homework Equations
P2=P1+pgh
The Attempt at a Solution
I thought you would just plug in the pressure in pascals to p1 and add [(1000 kg/m3)(9.8m/s2)(sqrt 2)]?
Okay find out the pressure in chamber 1. Pressure=force/area.
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#3
yesshh
3
0
So the answer is just 1.3x10^5 divided by 2?
Why?
#4
hollidca
11
0
No, 1.3x10^5 is pressure in chamber 2. Use the forumla given to you in the question to calcualte the pressure in chamber 1. You know the area of chamber 1 and you have calculated the pressure for chamber 1 so rearrange the formula pressure=force/area to give you the force.
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook.
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