Understanding Weight and Acceleration in a Bird's Flight Using Physics

AI Thread Summary
A bird in a closed cage weighs 25 N while sitting, and its mass is 0.5 kg. When the bird flies upward with an acceleration of 2 m/s², the spring balance should theoretically still record the same weight due to the closed system's total mass remaining constant. The bird generates lift by flapping its wings, creating air pressure that supports its weight against the cage. The discussion emphasizes that despite the bird's movement, the overall weight recorded by the spring balance does not change.
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Homework Statement


A bird is sitting in a large closed cage which is placed on a spring balance. It records a weight of
25 N. The bird (mass = 0.5 kg) flies upward in the cage with an acceleration of 2 m/s2. The spring
balance will now record a weight of -


Homework Equations





The Attempt at a Solution


i tried by calculating the mass of the spring balnce and then calculating the weight but the answer says same as earlier!1
 
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the weight will be same, as the cage is closed. total mass is constant. weight = mg.
 


supratim1 said:
the weight will be same, as the cage is closed. total mass is constant. weight = mg.

bird is not sitting now i mean its flapping its wings so that it is not in contact with the bars of the cage howz mass constant then
 


Does anyone know a way out of this prob??
 


the weight of the bird is supported by flapping its wings, which creates air pressure on the bottom of the cage. mass is always conserved.
 
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