Understanding Z-Pinch Plasma Behavior for Hydrogen Ion Stream Compression

  • Thread starter Thread starter lilrex
  • Start date Start date
  • Tags Tags
    Behavior Plasma
lilrex
Messages
64
Reaction score
0
I am still trying to get a handle on plasma behavior, if I had a gap intended to apply a field for the purpose of compressing a hydrogen ion stream, using the Z-pinch effect could one discharge a current through the ion stream to affect the Z-pinch? I am thinking that it would, that the electrons will flow through the ion stream and create the magnetic field that would influence the Ion stream.

I appreciate help on this, I am just kind of thinking out loud and this is a good place to have questions like this answered.
 
Last edited:
Physics news on Phys.org
more specifically speaking I know that plasma is highly conductive, I am just not sure how conductive a hydrogen ion beam is, at say 20Kev, it stands to reason that it would behave like any other plasma, but I don’t know much about it in this circumstance, like I am thinking (just hashing it out in my head) that the physical space between the ions, and the charge of the ions could prevent it from being neutral enough to become conductive (i am not sure if I am using the terminology right here).

maybe I should just try it and find out. good ole experimentations!
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

Similar threads

Back
Top