Uniform Acceleration-Algebraically

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An object displaced 19.6 m east while uniformly accelerating from rest has an average velocity of 5.00 m/s east. To find the rate of acceleration, the average velocity definition (displacement/time) can be used to extract time, calculated as 3.92 seconds. The kinematic equation Vf^2 = V0^2 + 2ax can then be applied, allowing for the isolation of acceleration. Despite initial confusion, understanding the relationship between average velocity, displacement, and time is crucial for solving the problem. The discussion emphasizes the importance of correctly applying kinematic equations to determine acceleration.
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b]1. Homework Statement [/b]

An object was displaced 19.6 m east while uniformly accelerating from rest. If the average velocity of the object was 5.00 m/s east, what was the rate of acceleration?

Homework Equations





The Attempt at a Solution



So my Vo=0
Vf= 5.00m/s east
x=19.6m

I need to calculate acceleration. Which equation do I use and how would I manipulate it?
 
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What is the definition of average velocity? Can you extract a time from this definition and the given information?

If you know the time and the distance traveled, do you know of a kinematic equation that relates them to the acceleration?
 
gneill said:
What is the definition of average velocity? Can you extract a time from this definition and the given information?

If you know the time and the distance traveled, do you know of a kinematic equation that relates them to the acceleration?

I don't believe I can extract a time from the problem. I tried using Vf^2 = V0^2 + 2ax. I do not know how to isolate the a. Can you help? My average velocity is my final velocity in this problem, is that correct?
 
alit00 said:
I don't believe I can extract a time from the problem. I tried using Vf^2 = V0^2 + 2ax. I do not know how to isolate the a. Can you help? My average velocity is my final velocity in this problem, is that correct?

You can extract a time. Go back to your notes and find the definition of average velocity.
 
gneill said:
You can extract a time. Go back to your notes and find the definition of average velocity.

Average velocity is displacement/time. Would my time be 3.92s?
 
alit00 said:
Average velocity is displacement/time. I do not have a time in this case.

You have the average velocity and you have the displacement...
 
gneill said:
You have the average velocity and you have the displacement...

I still do not understand. I tried every equation and am not getting the answer
 
alit00 said:
I still do not understand. I tried every equation and am not getting the answer

Look at the definition for average velocity. Can you identify the time variable in the definition?
Isolate the time variable in the equation.
 
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