Uniform circular motion car problem

AI Thread Summary
The maximum speed at which a cart can traverse a circular arch without losing contact with the track primarily depends on the radius of the arch and the acceleration due to gravity, rather than the mass of the cart or the person inside. At the point of losing contact, the normal force becomes zero, allowing for the determination of speed using the centripetal force equation. The correct centripetal force formula is Fc = mv²/r, not mv²/2r. The resulting velocity can be expressed as a function of the square root of the radius, indicating that mass does not influence the maximum speed. Thus, the critical factors are the radius of the arch and gravitational acceleration.
S[e^x]=f(u)^n
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Homework Statement


a cart with a person in passes over a circular arch at a constant speed v who's radius is r. Does the maximum speed the cart can go without leaving the tracks depend on the mass of the person, the mass of the cart, both, or neither?


Homework Equations


Fg=mg -Gravitational Force
Fc=(mv^2)/2r? -Centripetal force
Fn=? -Normal force


The Attempt at a Solution


Fc=Fg-Fn
i honestly don't know where to go from here? can anyone offer any hints... i need to figure it out by tomorrow afternoon. my gut says it depends on neither, but from math I've fiddled around with it seems to indicate it depends on both
 
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S[e^x]=f(u)^n;1463608 said:

Homework Statement


a cart with a person in passes over a circular arch at a constant speed v who's radius is r. Does the maximum speed the cart can go without leaving the tracks depend on the mass of the person, the mass of the cart, both, or neither?


Homework Equations


Fg=mg -Gravitational Force
Fc=(mv^2)/2r? -Centripetal force
Fn=? -Normal force


The Attempt at a Solution


Fc=Fg-Fn
i honestly don't know where to go from here? can anyone offer any hints... i need to figure it out by tomorrow afternoon. my gut says it depends on neither, but from math I've fiddled around with it seems to indicate it depends on both
that "2" in the denominator of your Fc equation doesn't belong there. Your equation Fc = Fg -Fn is good.
What is the value of Fn just as the cart would leave the tracks?
 
sorry about the 2, i don't know why i put it there. anyway Fn would be 0 on the cart, but so would the Fn for the person inside... wouldn't it? in which case the cart would leave the tracks at the same speed regardless of whether there was a person in there?... but is it still dependent on the weight of the car?
 
Well, weight (mg) is pulling down while the centrifugal force (mv2/r) would cause the cart to go tangent to the track. For the cart to stay on the track those two forces must be equal.

Set the forces equal and see what happens with respect to mass.
 
S[e^x]=f(u)^n;1463608 said:

Homework Statement


a cart with a person in passes over a circular arch at a constant speed v who's radius is r. Does the maximum speed the cart can go without leaving the tracks depend on the mass of the person, the mass of the cart, both, or neither?


Homework Equations


Fg=mg -Gravitational Force
Fc=(mv^2)/2r? -Centripetal force
Fn=? -Normal force


The Attempt at a Solution


Fc=Fg-Fn
i honestly don't know where to go from here? can anyone offer any hints... i need to figure it out by tomorrow afternoon. my gut says it depends on neither, but from math I've fiddled around with it seems to indicate it depends on both

what is special when the car is driven at the maximum speed so that it is just about to lose contact with the ground is that the normal force is zero. Isolate for the speed and you will have your answer. (btw, you should have mv^2/r, not mv^2/2r)
 
nrqed said:
what is special when the car is driven at the maximum speed so that it is just about to lose contact with the ground is that the normal force is zero. Isolate for the speed and you will have your answer. (btw, you should have mv^2/r, not mv^2/2r)

thanks, from what i can figure out the velocity at which the cart(regardless of mass) leaves the tracks is dependent solely on the square root of the radius. which sounds about right to me
 
S[e^x]=f(u)^n;1463947 said:
thanks, from what i can figure out the velocity at which the cart(regardless of mass) leaves the tracks is dependent solely on the square root of the radius. which sounds about right to me

correct. (and it depends on the acceleration due to gravity...the max speed on th emoon would be different ;-) )
 
thanks!
 
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