Uniform Circular Motion confusion.

AI Thread Summary
In the discussion about uniform circular motion, a participant expresses confusion over the formula v = 2πrω, believing it should be v = 2πr²ω. The conversation revolves around the relationship between tangential speed (v) and angular speed (ω), specifically in the context of a cube placed in a rotating funnel. The problem involves determining the conditions under which the cube remains stationary relative to the funnel, leading to the derivation of the force equation F = 4π²m rω². The confusion is compounded by formatting issues with mathematical symbols, and a suggestion is made to use consistent LaTeX formatting for clarity.
DavidAlan
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How can v = 2\pir\omega?

I've looked at this a hundred different ways... I've found that v = 2\pir2\omega only.
 
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You'll have to give us at least a hint of what you are talking about. :-p

Please explain the problem you are trying to solve and what your equations are describing.

For uniform circular motion of radius r, the tangential speed v (measured in m/s) is related to the angular speed ω (measured in rad/s) by the formula: v = ωr.
 
The issue arose in the following problem;

A very small cube of mass m is placed on the inside of a funnel rotating around a vertical axis at a constant rate of v revolutions per second. The wall of the funnel makes an angle \theta with the horizontal. The coefficient of static friction between cube and funnel is \mus and the center of the cube is at a distance r from the axis of rotation. Find (a) largest and (b) smallest values of v for which the cube will not move with respect to the funnel.

I consulted my handy dandy solutions manual and it wanted to work with the assumption that speed in this case = 2 \pi r \omega.

I'm still scratching my head.

The purposes of defining the speed in this way is to get that F = 4 \pi2 m r \omega2.

Sorry for the ambiguity, I thought that someone would recognize the issue right away.

BTW, I don't know what's up with the editing but pi and omega are not powers. They just look that way... :blushing:
 
DavidAlan said:
I consulted my handy dandy solutions manual and it wanted to work with the assumption that speed in this case = 2 \pi r \omega.

Makes no sense to me. What textbook is this?
BTW, I don't know what's up with the editing but pi and omega are not powers. They just look that way...
That's because you're mixing Latex and regular text. Try doing it all with Latex, like this: 2 \pi r \omega. Even better is to use 'inline' latex, using the 'itex' tag: 2 \pi r \omega.
 
It's from Resnick Haliday and Krane 4th edition volume 1.
 
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