Uniform circular motion of satellite

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An Earth satellite orbits 735 km above the surface with a period of 99.3 minutes. The user initially calculated the satellite's speed and centripetal acceleration but found the results incorrect. They clarified that the radius for calculations should include the Earth's radius in addition to the altitude. After correcting the radius to account for the Earth's size, they successfully solved the problem. The discussion emphasizes the importance of accurately determining the radius in orbital motion calculations.
iamkristing
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1. An Earth satellite moves in a circular orbit 735 km above the Earth's surface. The period of the motion is 99.3 min. (a) What is the speed of the satellite?(b) What is the magnitude of the centripetal acceleration of the satellite?



2. a = v^2/r

T=2(pi)r/v


3. i needed the solution in meters per second and found r = 735000 and T =5958. I plugged into the equations and solved and get 775 m for the speed and .818 for the magnitude. Both answers are incorrect but I'm unable to come up with the correct ones.
 
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735km is the distance above the surface, r should be the distance from the point it is rotating around
 
right so would you add the radius of the Earth to 735 as well?
 
nevermind i got it. thanks!
 
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