# Uniform continuity, cauchy sequences

## Homework Statement

If f:S->Rm is uniformly continuous on S, and {xk} is Cauchy in S show that {f(xk)} is also cauchy.

## The Attempt at a Solution

Since f is uniformly continuous,

$$\forall$$$$\epsilon$$>0, $$\exists$$$$\delta$$>0: $$\forall$$x, y ∈ S, |x-y| < $$\delta$$ => |f(x)-f(y)| < $$\epsilon$$

So I said that let x, y be sequences, {xn} and {xp}

Since {xn} is Cauchy, $$\forall$$$$\epsilon$$>0, $$\exists$$N : $$\forall$$n,p $$\geq$$ N , |xn-xp| < $$\epsilon$$

Then using the fact that f is uniformly continuous, |f(xn)-f(xp)| < $$\epsilon$$

I don't think this is right.. am I allowed to replace those x's and f(x)'s with the sequences for example?