Uniform distribution on the disc

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SUMMARY

The discussion focuses on deriving the marginal probability density functions (pdf) for a uniform distribution over a disc of radius 1 in R², defined as D = {(x,y) in R² | x² + y² ≤ 1}. The joint distribution is established as 1/π for points within the disc, with the area of the disc calculated as π. The probability is confirmed to be 1, leading to the marginal pdfs being integrals of the joint distribution over the respective variables.

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  • Understanding of joint probability distributions
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  • Basic concepts of uniform distribution in probability theory
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Homework Statement



consider a disc of radius 1 in the plane D in R^2
D = {(x,y) in R^2 | x^2 + y^2 <=1 }
what is the marginal pdf of x and y

Homework Equations





The Attempt at a Solution


so the joint distribution of xy is 1/Pi for x^2 + y^2 <=1 right?
but how exactly? "density" = "probability" / "area"
area = Pi since Pi*(1)^2 what about the probability? why is it 1?

what is the marginal pdf of x and y?
is it integral of 1/Pi from -infinity to +infinity wrt to y for marginal pdf of x?
 
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why did you post this in two locations? look at your other post.
 

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