Uniqueness of Inverse Operators Theorem and Proof

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The discussion centers on the uniqueness of inverse operators, specifically that if both left and right inverses exist for an operator A, they are equal and unique. The proof provided shows that if A_l^{-1}A = I and AA_r^{-1} = I, then A_l^{-1} must equal A_r^{-1}. The confusion arises from the assertion that the proof holds for any pair of inverses, leading to the question of how multiple inverses could exist if they are proven to be equal. The argument emphasizes that if A had two distinct inverses, the same proof would demonstrate their equality, reinforcing the concept of a single unique inverse operator. The conclusion is that the uniqueness of the inverse operator is a fundamental aspect of linear algebra.
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Homework Statement


Theorem
If, for given A, both operators A_l^{-1} and A_r^{-1} exist, they are unique and
A_l^{-1}=A_r^{-1}

The proof is rather straightforward, at least the first part of it:
A_l^{-1}A=I/\leftarrow A_r^{-1}
A_l^{-1}AA_r^{-1}=A_r^{-1} (1)

A_l^{-1}A=I/\rightarrow A_l^{-1}
A_l^{-1}AA_r^{-1}=A_l^{-1} (2)

Therefore
A_l^{-1}=A_r^{-1}

However, then they say that this proof holds for any pair of operators A_l^{-1} and A_r^{-1} (which I can't deny) and that eqs (1) and (2) ensure there exists only one such pair, which I can't understand. I would be very grateful if someone explains to me why is that.
 
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If you've proved A_l^(-1)=A_r^(-1) then there's not really a pair. They are both the same operator, just call it A^(-1). Now suppose A had two different inverses, can you prove they are equal? It's really the same proof you just gave.
 
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