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MD_Programmer

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## Homework Statement

The power available (output) is measured by the velocity at which you are moving and the thrust

required to create that movement. NOTE: Conversions for proper units are provided below

equation.

Power Available: Pout = Tc * v

where: Pout = power available (watts)

Tc = Calibrated thrust (grams)

v = wind tunnel velocity (m/s)

In order to determine the efficiency, the units must cancel. To convert the units so that the output

power is in watts, use the following information:

can't get the power right help?

## Homework Equations

1 gram = 0.002205 lbs.

1 m/s = 3.28 ft/s

1 horsepower = 550 lb*ft/sec

1 horsepower = 745.7 watts

v = 3 m/s

Tc = 0.0040 g

## The Attempt at a Solution

(0.0040*0.002205) = 8.82 E-6

(3*3.28) = 9.84 ft/s

((8.82 E-6 * 9.84) *550) / 745.7 = 6.401212284 E-5 watts

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