Unit Tangent for a Curve: Finding T(t) using the Product Rule

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SUMMARY

The discussion centers on finding the unit tangent vector T(t) for the curve defined by the vector function r(t) = 〈sin(t) − t cos(t), cos(t) + t sin(t), 5t² + 7〉. The correct derivative, r'(t), is calculated as 〈cos(t) + t sin(t), -sin(t) + t cos(t), 10t〉. The unit tangent vector is determined by normalizing r'(t) using the formula T(t) = r'(t) / |r'(t)|, where |r'(t)| is the magnitude of the derivative. The discussion highlights the necessity of applying the product rule correctly in differentiation.

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Homework Statement



r(t) = 〈sin(t) − t cos(t), cos(t) +t sin(t), 5 t2 + 7 〉

Find the unit tangent. T(t)=


The Attempt at a Solution



r'(t) = <cos(t) + tsin(t), -sin(t) + tcos(t), 10t>

T(t) = r'(t)/ |r'(t)|

|r(t)| = sqrt( 1 + 101t^2)

And so on.
Supposably according to the homework I'm wrong, completely wrong.
 
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Your derivative is wrong, completely wrong. You aren't using the product rule.
 

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